diff --git a/Doc/Sd1/languageFundamentals.xml b/Doc/Sd1/languageFundamentals.xml
index 8fa818bce5825321daf49c51468cc1e02bcc5bd3..5e410707fcf7244a1368359009a946c7918c22e2 100644
--- a/Doc/Sd1/languageFundamentals.xml
+++ b/Doc/Sd1/languageFundamentals.xml
@@ -1194,7 +1194,7 @@ Seconds:31</programlisting>
           <qandaentry>
             <question>
               <para>A programmer named Joe intends to map <code>long</code>
-              values to <code>int</code> values. This requires mapping the
+              values to <code>int</code> values. This requires scaling the
               <code>long</code> data type's range <inlineequation>
                   <m:math display="inline">
                     <m:mrow>
@@ -1229,7 +1229,7 @@ Seconds:31</programlisting>
                       <m:mo>]</m:mo>
                     </m:mrow>
                   </m:math>
-                </inlineequation> to an <code>int</code>'s range of
+                </inlineequation> down to an <code>int</code>'s range of
               <inlineequation>
                   <m:math display="inline">
                     <m:mrow>
@@ -1264,142 +1264,75 @@ Seconds:31</programlisting>
                       <m:mo>]</m:mo>
                     </m:mrow>
                   </m:math>
-                </inlineequation>. Joe's first attempt reads:</para>
+                </inlineequation>. </para>
 
-              <programlisting language="java">final long longValue = ...;
-  ...      
-final int reducedValue = (int) (longValue / (2 * (Integer.MAX_VALUE + 1)));</programlisting>
-
-              <para>Unfortunately the results are not promising. May you help
-              Joe correcting his error? Provide an example showing the
-              problem.</para>
-            </question>
-
-            <answer>
-              <para>We consider:</para>
-
-              <programlisting language="java">final long longValue = Long.MAX_VALUE;
-      
-final int reducedValue = (int) (longValue / (2 * (Integer.MAX_VALUE + 1)));
-System.out.println(reducedValue);</programlisting>
-
-              <para>The intended result should assign Integer.MAX_VALUE to the
-              variable <code>reducedValue</code>. Actually Joe created a
-              runtime error:</para>
-
-              <programlisting language="none">Exception in thread "main" java.lang.ArithmeticException: / by zero</programlisting>
-
-              <para>Joe's idea is dividing a long value reducing it to an
-              <code>int</code> accordingly. Since
-              <code>Integer.MAX_VALUE</code> is equal to <inlineequation>
+              <para>Joe thinks of dividing long values by <inlineequation>
                   <m:math display="inline">
-                    <m:mrow>
-                      <m:msup>
-                        <m:mi>2</m:mi>
-
-                        <m:mi>31</m:mi>
-                      </m:msup>
-
-                      <m:mo>-</m:mo>
+                    <m:msup>
+                      <m:mi>2</m:mi>
 
-                      <m:mi>1</m:mi>
-                    </m:mrow>
+                      <m:mi>32</m:mi>
+                    </m:msup>
                   </m:math>
-                </inlineequation> Joe assumes <code>(2 * (Integer.MAX_VALUE +
-              1)</code> to be equal to <inlineequation>
+                </inlineequation>. As a result a long value of <inlineequation>
                   <m:math display="inline">
                     <m:mrow>
-                      <m:mrow>
-                        <m:mi>2</m:mi>
-
-                        <m:mo>×</m:mo>
-
-                        <m:msup>
-                          <m:mi>2</m:mi>
-
-                          <m:mi>31</m:mi>
-                        </m:msup>
-                      </m:mrow>
-
-                      <m:mo>=</m:mo>
+                      <m:mo>-</m:mo>
 
                       <m:msup>
                         <m:mi>2</m:mi>
 
-                        <m:mi>32</m:mi>
+                        <m:mi>63</m:mi>
                       </m:msup>
                     </m:mrow>
                   </m:math>
-                </inlineequation>. Dividing a <code>long</code> indeed maps
+                </inlineequation> will be reduced to the intended value of
               <inlineequation>
                   <m:math display="inline">
                     <m:mrow>
-                      <m:mo>[</m:mo>
-
-                      <m:mrow>
-                        <m:mrow>
-                          <m:mo>-</m:mo>
-
-                          <m:msup>
-                            <m:mi>2</m:mi>
-
-                            <m:mi>63</m:mi>
-                          </m:msup>
-                        </m:mrow>
-
-                        <m:mo>,</m:mo>
-
-                        <m:mrow>
-                          <m:msup>
-                            <m:mi>2</m:mi>
-
-                            <m:mi>63</m:mi>
-                          </m:msup>
-
-                          <m:mo>-</m:mo>
+                      <m:mo>-</m:mo>
 
-                          <m:mi>1</m:mi>
-                        </m:mrow>
-                      </m:mrow>
+                      <m:msup>
+                        <m:mi>2</m:mi>
 
-                      <m:mo>]</m:mo>
+                        <m:mi>31</m:mi>
+                      </m:msup>
                     </m:mrow>
                   </m:math>
-                </inlineequation> to <inlineequation>
+                </inlineequation>. Since <inlineequation>
                   <m:math display="inline">
-                    <m:mrow>
-                      <m:mo>[</m:mo>
-
-                      <m:mrow>
-                        <m:mrow>
-                          <m:mo>-</m:mo>
-
-                          <m:msup>
-                            <m:mi>2</m:mi>
+                    <m:msup>
+                      <m:mi>2</m:mi>
 
-                            <m:mi>31</m:mi>
-                          </m:msup>
-                        </m:mrow>
+                      <m:mi>32</m:mi>
+                    </m:msup>
+                  </m:math>
+                </inlineequation> seems to be equal to <code>2 *
+              (Integer.MAX_VALUE + 1))</code> (why?) Joe's first attempt
+              reads:</para>
 
-                        <m:mo>,</m:mo>
+              <programlisting language="java">final long longValue = ...;
+  ...      
+final int reducedValue = (int) (longValue / (2 * (Integer.MAX_VALUE + 1)));</programlisting>
 
-                        <m:mrow>
-                          <m:msup>
-                            <m:mi>2</m:mi>
+              <para>Unfortunately the results are not promising. May you help
+              Joe correcting his error? Provide an example showing the
+              problem.</para>
+            </question>
 
-                            <m:mi>31</m:mi>
-                          </m:msup>
+            <answer>
+              <para>We consider:</para>
 
-                          <m:mo>-</m:mo>
+              <programlisting language="java">final long longValue = Long.MAX_VALUE;
+      
+final int reducedValue = (int) (longValue / (2 * (Integer.MAX_VALUE + 1)));
+System.out.println(reducedValue);</programlisting>
 
-                          <m:mi>1</m:mi>
-                        </m:mrow>
-                      </m:mrow>
+              <para>The intended result should assign Integer.MAX_VALUE to the
+              variable <code>reducedValue</code>. Actually Joe's attempt
+              creates a runtime error:</para>
 
-                      <m:mo>]</m:mo>
-                    </m:mrow>
-                  </m:math>
-                </inlineequation>.</para>
+              <programlisting language="none">Exception in thread "main" java.lang.ArithmeticException: / by zero</programlisting>
 
               <para>Unfortunately Joe's assumption is seriously flawed:</para>